SOLUTION: Write an equation of the line that passes through the given point and is perpendicular to the graph of the given equation. (-8,3) y+4=-(2/3)(x-2)

Algebra ->  Coordinate-system -> SOLUTION: Write an equation of the line that passes through the given point and is perpendicular to the graph of the given equation. (-8,3) y+4=-(2/3)(x-2)      Log On


   

Question 734960: Write an equation of the line that passes through the given point and is perpendicular to the graph of the given equation. (-8,3) y+4=-(2/3)(x-2)
Answer by josgarithmetic(39838) About Me  (Show Source):
You can put this solution on YOUR website!
Interesting that you showed your given line in almost correctly point-slope form as plain text. Your post is now edited for this correction to eliminate possible confusion, ------

The slope that you will want is the negative reciprocal of %28-%282%2F3%29%29, which will be 3%2F2. You now expect an equation for your desired line to be y-v=%283%2F2%29%2A%28x-u%29, where the point (u, v) is any point which you want your line to contain. The given point for (u, v) is (-8, 3), so just substitute those values:
y-%283%29=%283%2F2%29%2A%28x-%28-8%29%29
and the rest to be done is a couple steps of arithmetic.