SOLUTION: Write an equation of the line that passes through the given point and is perpendicular to the graph of the given equation. (-8,3) y+4=-(2/3)(x-2)

Question 734960: Write an equation of the line that passes through the given point and is perpendicular to the graph of the given equation. (-8,3) y+4=-(2/3)(x-2)
Answer by josgarithmetic(39838) (Show Source): You can put this solution on YOUR website!
Interesting that you showed your given line in almost correctly point-slope form as plain text. Your post is now edited for this correction to eliminate possible confusion, ------

The slope that you will want is the negative reciprocal of , which will be . You now expect an equation for your desired line to be , where the point (u, v) is any point which you want your line to contain. The given point for (u, v) is (-8, 3), so just substitute those values:

and the rest to be done is a couple steps of arithmetic.
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