Hi,

Using the standard slope-intercept form for an equation of a line y = mx + b

  where m is the slope and b the y-intercept.

line whose x intercept is -3 and which is perpendicular to the line 3x+5y-8=0

3x + 5y - 8 = 0   OR  

New Line perpendicular to the above:  m = 5/3

 y = (5/3)x + b

 0 = (5/3)·-3 + b   |Using x-intercept = -3:  |(x,y):(-3,0)  to solve for b

 5 = b

 y = (5/3)x + 5 

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