# SOLUTION: Write the equation of the line that is perpendicular to the line y = 2x + 2 and passes through the point (6, 3).

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 Click here to see ALL problems on Coordinate-system Question 623496: Write the equation of the line that is perpendicular to the line y = 2x + 2 and passes through the point (6, 3).Answer by math-vortex(472)   (Show Source): You can put this solution on YOUR website!```Hi, there-- The Problem: Write the equation of the line that is perpendicular to the line y = 2x + 2 and passes through the point (6, 3). The Solution: We need to find the slope of the perpendicular line. Then we can find an equation for the line using point-slope form. The original equation y = 2x + 2 is in slope-intercept form (y=mx+b) so we can read the slope right off the equation. The slope m is 2. The slope of the perpendicular line will always have the slope -1/m. In this case, the slope of the perpendicular line is -1/m=-1/2. The point-slope form for a line is y-y[1] = m(x-x[1]), where m is the slope and (x[1],y[1]) is a point on the line. The point (x[1],y[1]) is (6,3), so the equation is y - (3) = (-1/2)(x - 6) You can simplify this a bit if we want to, but it's not essential. y-3 = (-1/2)x+3 y = (-1/2)x+6 . Feel free to email if you have questions about the solution. Ms.Figgy math.in.the.vortex@gmail.com ```