SOLUTION: . Find the equation, in slope-intercept form, of the line that passes through the points (-3, 1) and (-2, -5).

Question 60346: . Find the equation, in slope-intercept form, of the line that passes through the points (-3, 1) and (-2, -5).
Answer by tutorcecilia(2152) (Show Source): You can put this solution on YOUR website!
y=mx+b [The slope-intercept form of the equation of a line]
Slope=m=(y2-y1)/(x2-x1) [The formula for finding the slope of a line]
(-3, 1) and (-2, -5) [The given points]
.
Slope=m=(-5-1)/(-2-(-3) =(-6/1)=-6 [Plug-in the given points]
m=-6 [The slope of the line]
.
y=mx+b [Plug-in the known values and solve for b]
1=(-6)(-3)+b [I used points (-3, 1) and the slope (-6), but any point is OK]
1=18+b [Solve for b]
-17=b
.
y=mx+b [Plug-in the values of the slope and the y-intercept (b)]
y=-6x-17 [The slope-intercept form of the equation of the line].
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