# SOLUTION: Would someone be able to help me on this problem? I need to solve the following systems of linear inequalitys graphically. I have a x-axis and a y-axis. 3x - y

Algebra ->  Algebra  -> Coordinate-system -> SOLUTION: Would someone be able to help me on this problem? I need to solve the following systems of linear inequalitys graphically. I have a x-axis and a y-axis. 3x - y      Log On

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 Algebra: Coordinate systems, graph plotting, etc Solvers Lessons Answers archive Quiz In Depth

 Click here to see ALL problems on Coordinate-system Question 58138This question is from textbook Beginning Algebra : Would someone be able to help me on this problem? I need to solve the following systems of linear inequalitys graphically. I have a x-axis and a y-axis. 3x - y < (less than) 6 there is a line under the < x > = 1 y < (less than) 3 there is a line under the < Thank you, AshleyThis question is from textbook Beginning Algebra Answer by ankor@dixie-net.com(15747)   (Show Source): You can put this solution on YOUR website!3x - y < (less than) 6 there is a line under the < When there is a line under the < is means less or equal to : For graphing purposes we want it in the "y =" form -y <= 6 - 3x To get a positive y, mult the equation by -1, then we have to reverse the inequality sign, we then have: y >= 3x - 6; graphed as a green line, area of interest is = or above the line : x > = 1, you will have draw this in yourself as a vertical line going through x = 1; area of interest is is = to x = 1 and to right of 1 : y <= 3 graphed as a horizontal red line, area of interest is = or below the line : Just to emphasize the area of interest; it is area bounded by all this lines and includes the point x=2, y=2 : Does this help you?