SOLUTION: Would someone be able to help me on this problem? I need to solve the following systems of linear inequalitys graphically. I have a x-axis and a y-axis. 3x

SOLUTION: Would someone be able to help me on this problem? I need to solve the following systems of linear inequalitys graphically. I have a x-axis and a y-axis. 3x - y

Question 58138This question is from textbook Beginning Algebra
: Would someone be able to help me on this problem?
I need to solve the following systems of linear inequalitys graphically.
I have a x-axis and a y-axis.

3x - y < (less than) 6 there is a line under the <
x > = 1
y < (less than) 3 there is a line under the <
Thank you,
Ashley This question is from textbook Beginning Algebra

Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
3x - y < (less than) 6 there is a line under the <
When there is a line under the < is means less or equal to
:
For graphing purposes we want it in the "y =" form
-y <= 6 - 3x
To get a positive y, mult the equation by -1, then we have to reverse the
inequality sign, we then have:
y >= 3x - 6; graphed as a green line, area of interest is = or above the line
:
x > = 1, you will have draw this in yourself as a vertical line going through
x = 1; area of interest is is = to x = 1 and to right of 1
:
y <= 3 graphed as a horizontal red line, area of interest is = or below the line
:
Just to emphasize the area of interest; it is area bounded by all this lines and
includes the point x=2, y=2

:
Does this help you?
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