SOLUTION: Find the equation of the line passing through (-1,1) and parallel to x+2y-13=0. Give answer in slope-intercept form. (y=mx+b)

Question 570151: Find the equation of the line passing through (-1,1) and parallel to x+2y-13=0. Give answer in slope-intercept form. (y=mx+b)
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
Find the equation of the line passing through (-1,1) and parallel to x+2y-13=0. Give answer in slope-intercept form. (y=mx+b)
Begin by determining slope of:
x+2y-13=0
2y-13=-x
2y=-x+13
y=(-1/2)x + 13/2
slope is -1/2
.
plug slope (-1/2) and given point (-1,1) into "point-slope" form:
y - y1 = m(x - x1)
y - 1 = (-1/2)(x - (-1))
y - 1 = (-1/2)(x + 1)
y - 1 = (-1/2)x - 1/2
y = (-1/2)x - 1/2 + 1
y = (-1/2)x - 1/2 + 2/2
y = (-1/2)x + 1/2 (this is what they're looking for)

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