SOLUTION: 1.(a)If (p+1)x+y=3 and 3y-(p-1)x=4 are perpendicular to each other,find the value of p. (b)If y+(2p+1)x+3=0 and 8y-(2p-1)x=5 are mutually perpendicular,find the value of p. 2.The

Question 550586: 1.(a)If (p+1)x+y=3 and 3y-(p-1)x=4 are perpendicular to each other,find the value of p.
(b)If y+(2p+1)x+3=0 and 8y-(2p-1)x=5 are mutually perpendicular,find the value of p.
2.The co-ordinates of the vertex A of a square ABCD are (1,2) and the equation of the diagonal BD is x+2y=10.Find the equation of the other diagonal and the co-ordinates of the centre of the square.

Answer by KMST(5328) (Show Source): You can put this solution on YOUR website!
1.(a)If (p+1)x+y=3 and 3y-(p-1)x=4 are perpendicular to each other, the product of their slopes is -1. I can use that fact to find the value of p.
The slope of -->
is
The slope of --> -->
is
The product of the slopes is
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There are two solutions and
(b)If y+(2p+1)x+3=0 and 8y-(2p-1)x=5 are mutually perpendicular, the product of their slopes is -1. I can use that fact to find the value of p.
The slope of -->
is
The slope of --> -->
is
The product of the slopes is
--> --> --> -->
There are two solutions and
2.The co-ordinates of the vertex A of a square ABCD are (1,2) and the equation of the diagonal BD is x+2y=10.Find the equation of the other diagonal and the co-ordinates of the centre of the square.
I solved this problem recently. It was submitted as question # 550393.
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