SOLUTION: Find the equation of the circle centered at (4,6) and passing through the point (2,2). Thank you I'm having a hard time with circle equations!

Question 530469: Find the equation of the circle centered at (4,6) and passing through the point (2,2).
Thank you I'm having a hard time with circle equations!
Found 2 solutions by jim_thompson5910, stanbon:
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Start with the general equation of a circle.

Plug in and (since the center is the point (h,k) ).

Plug in and (this is the point that lies on the circle, which is in the form (x,y) ).

Combine like terms.

Square each term.

Add.

So because , , and , this means that the equation of the circle with center (4,6) that goes through the point (2,2) is

.

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Find the equation of the circle centered at (4,6)
and passing through the point (2,2).
----
radius = sqrt[(6-2)^2+(4-2)^2] = sqrt[20)
----
Form: (x-h)^2 + (y-k)^2 = r^2
---
Your Problem:
(x-4)^2 + (y-6)^2 = 20
==========================
Cheers,
Stan H.
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