SOLUTION: Given the function f(x) = -x^2+8x
a. Determine the vertex,
b. List the axis of symmetry,
c. calculate the y-intercept,
d. find an additional point on the graph, and
e. graph t
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Question 524664: Given the function f(x) = -x^2+8x
a. Determine the vertex,
b. List the axis of symmetry,
c. calculate the y-intercept,
d. find an additional point on the graph, and
e. graph the function.
Please show all of your work.
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Given any second degree (quadratic) polynomial function of the form:
\ =\ ax^2\ +\ bx\ +\ c)
The coordinates of the vertex are found by:
 = \rho\left(\frac{-b}{2a}\right)\ =\ a\left(\frac{-b}{2a}\right)^2\ +\ b\left(\frac{-b}{2a}\right)\ +\ c)
And the vertex is thus )
The equation of the axis of symmetry is:
The 
-intercept is the point \right))
and \ =\ a(0)^2\ +\ b(0)\ +\ c\ =\ c)
. HINT: 
for your particular problem.
By symmetry, \right))
is a point on the graph.
Plot the three points you have derived so far and then draw a smooth curve through them.
John
My calculator said it, I believe it, that settles it
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