SOLUTION: Determine whether or not the equation has a circle in it's graph
4x^2+4y^2-24x-40y+36=0
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Question 514401: Determine whether or not the equation has a circle in it's graph
4x^2+4y^2-24x-40y+36=0
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Determine whether or not the equation has a circle in it's graph
4x^2+4y^2-24x-40y+36=0
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Divide thru by 4 to get:
x^2-6x + y^2-10y = -36
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Complete the square on the x and on the y terms:
x^2-6x+9 + y^2-10y+25 = -36+9+25
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(x-3)^2 + (y-5)^2 = -2
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Not a circle because radius would be sqrt(-2) = i*sqrt(2)
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Cheers,
Stan H.
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