SOLUTION: Find the coordinates of the turning point of the curve {{{y = 6 + 4x - x^2}}} (by expressing this equation in the form {{{a - (x + b)^2}}} ) and determine the nature of this turnin

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Question 474084: Find the coordinates of the turning point of the curve (by expressing this equation in the form ) and determine the nature of this turning point.
*Please answer as soon as possible bro :)
Found 2 solutions by nerdybill, ewatrrr:
Answer by nerdybill(7384)   (Show Source): You can put this solution on YOUR website!

"turning point" is at the vertex, where the x coordinate is at:
x = -b/(2a)
x = -4/(2(-1))
x = -4/(-2)
x = 2
.
find y by plugging it into equation:




.
turning point is at (2,10)
Since the coefficient associated with the x^2 is negative, it is a parabola that opens downwards.
This means (2,10) is the peak.
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 

Hi,

Find the coordinates of the turning point of the curve 

  |Turning point is the Vertex of the Parabola

  y = -[x^2 - 4x] + 6

  y = -[(x-2)^2 - 4] + 6

  y = -(x-2)^2 + 10  V(2,10), the turning point

       a = -1 -1<0, Parabola opens downward





 

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