SOLUTION: i) Express {{{6 + 4x - x^2}}} in the form {{{a - (x + b)^2}}}, where a and b are integers. ii) Find the coordinates of the turning point of the curve {{{y = 6 + 4x - x^2}}} and de

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Question 473619: i) Express in the form , where a and b are integers.
ii) Find the coordinates of the turning point of the curve and determine the nature of this turning point.
*Please answer as soon as possible bro :)

Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 
Hi,
Find the coordinates of the turning point of the curve
|Turning point is the Vertex of the Parabola
y = -[x^2 - 4x] + 6
y = -[(x-2)^2 - 4] + 6
y = -(x-2)^2 + 10 V(2,10), the turning point
a = -1 -1<0, Parabola opens downward, turning point is a maximum


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