SOLUTION: I need to find the equations of the lines joining the pairs of points: 
1. (3,4) (-1,0)
2. (0,6) (4,-2)
I am so stuck with this one!! 
Algebra.Com
Question 469031:  I need to find the equations of the lines joining the pairs of points: 
1. (3,4) (-1,0)
2. (0,6) (4,-2)
I am so stuck with this one!!  
Answer by mananth(16946)   (Show Source): You can put this solution on YOUR website!
 x1		y1	x2	y2				
3		4	-1	0				
								
slope m =		(y2-y1)/(x2-x1)						
(	0	-	4	)/(	-1	-	3	) 
(	-4	/	-4	)  				
m=		1.00						 
								
Plug value of  the slope  and point (3,4) in	
Y 	=	m	x 	+	b			
4.00	=	3	+	b				
b=	4		3					
b=	1							
So the equation  will be								
Y 	=x+1
x1		y1	x2	y2				
0		6	4	-2				
								
slope m =		(y2-y1)/(x2-x1)						
(	-2	-	6	)/(4-0) 
(	-8	/	4	)  				
m=		-2.00						 
								
Plug value of  the slope  and point (0,6) in	
Y 	=	m	x 	+	b			
6.00	=	0	+	b				
b=	6		0					
b=	6							
So the equation  will be								
Y 	=	-2	x 	+	6			
			
m.ananth@hotmail.ca								
 
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