Hi, Previously posted.

Using the vertex form of a parabola,  where(h,k) is the vertex

a. f (x) = x^2    |Parabola: Vertex Pt(0,0). y-axis the line of symmetry



b. f(x) = x^2+4x = (x+2)^2-4   |Parabola: Vertex Pt(-2,-4). x = -2 the line of symmetry



c. f(x) = x^2-4x +3 = (x-2)^2 -1 |Parabola: Vertex Pt(2,-1). x = 2 the line of symmetry



 

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