# SOLUTION: Find the length of the perpendicular from R to KO when R (3 , 4), K ( 3 , 1) and O ( 8 , 4) are the vertices of a right-angled triangle. :) =) *Please answer as soon as possi

Algebra ->  Algebra  -> Coordinate-system -> SOLUTION: Find the length of the perpendicular from R to KO when R (3 , 4), K ( 3 , 1) and O ( 8 , 4) are the vertices of a right-angled triangle. :) =) *Please answer as soon as possi      Log On

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 Click here to see ALL problems on Coordinate-system Question 408099: Find the length of the perpendicular from R to KO when R (3 , 4), K ( 3 , 1) and O ( 8 , 4) are the vertices of a right-angled triangle. :) =) *Please answer as soon as possible. :)Answer by lwsshak3(6764)   (Show Source): You can put this solution on YOUR website!Find the length of the perpendicular from R to KO when R (3 , 4), K ( 3 , 1) and O ( 8 , 4) are the vertices of a right-angled triangle. .. What you have here is a right triangle with legs of 5(RO) and 3(RK) and a hypotenuse (OK). Using the pythagorean theorem, OK = sqrt(5^2+3^2)=sqrt(34) Let x=length of the perpendicular from R to KO, and P, the point at which the perpendicular lands on KO. We can now see two similar triangles: the first is the larger one,RKO, and a smaller,RKP of which x is one of the legs. We can now set up a proportion. RO/KO=RP/RK 5/sqrt(34)=x/3 x=15/sqrt(34) ans: x=2.57