SOLUTION: Find the x-intercept of the straight line
passing through P = (2, 3) and perpendicular
to
y + 3x = 8 .
Algebra.Com
Question 397155: Find the x-intercept of the straight line
passing through P = (2, 3) and perpendicular
to
y + 3x = 8 .
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Start with the given equation.
Subtract from both sides.
Rearrange the terms.
We can see that the equation has a slope and a y-intercept .
Now to find the slope of the perpendicular line, simply flip the slope to get . Now change the sign to get . So the perpendicular slope is .
Now let's use the point slope formula to find the equation of the perpendicular line by plugging in the slope and the coordinates of the given point
.
Start with the point slope formula
Plug in , , and
Distribute
Multiply
Add 3 to both sides.
Combine like terms. note: If you need help with fractions, check out this solver.
So the equation of the line perpendicular to that goes through the point
is .
Here's a graph to visually verify our answer:
Graph of the original equation (red) and the perpendicular line (green) through the point
.
If you need more help, email me at jim_thompson5910@hotmail.com
Also, feel free to check out my tutoring website
Jim
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