SOLUTION: The line through A(3,1) perpendicular to x - 4y = 8 meets the x-axis at P and the y-axis at Q. Calculate the ratio PA : AQ.

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Question 389043: The line through A(3,1) perpendicular to x - 4y = 8 meets the x-axis at P and the y-axis at Q. Calculate the ratio PA : AQ.
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!

Hi
Note: the standard slope-intercept form for an equation of a line is y = mx + b
where m is the slope and b the y-intercept.
line through A(3,1) perpendicular to x - 4y = 8 OR y = (1/4)x - 2
Perpendicular lines have slopes that are negative reciprocals of one another
New line y = -4x + b using ordered pair Pt(3,1) to solve for b
1 = -12 + b b = 13
y = -4x + 13 P(13/4,0) and Q(0,13)on this line
Calculate the ratio PA : AQ
PA Distance would be: P(13/4,0)and A(3,1)

PA =
AQ Distance would be: A(3,1)and Q(0,13)
AQ =
PA:AQ would be 1.031:12.369


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