SOLUTION: Hi - Need assistance and my tutor is gone for weekend. It is graphing y = -x^2 and y = -(x-2)^2 + 1 I did the y = -x^2 it is a perabola that opens down from zero and then goe

Question 376786: Hi - Need assistance and my tutor is gone for weekend. It is graphing
y = -x^2 and y = -(x-2)^2 + 1
I did the y = -x^2 it is a perabola that opens down from zero and then goes out to (-1,-1) (1,-1) (-2,-4)(2,-4) but am confused on the second one - I know that it shifts but uncertain as to formula
The first time I did it I shifted it to (1,2) then down one and over one. The next time I did it I shifted it to (2,1) and then down. Am stuck
Thanks for your assistance.
Carol
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
y = -(x-2)^2 + 1
y=-(x^2-4x+4)+1
y=-x^2+4x-4+1
y=-x^2+4x+3
...

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