SOLUTION: Find the two remaining vertices of square ABCD that has A=(-2,1), B=(6,-5) and a vertex in quadrant III.

Question 37610: Find the two remaining vertices of square ABCD that has A=(-2,1), B=(6,-5) and a vertex in quadrant III.
Answer by venugopalramana(3286) (Show Source): You can put this solution on YOUR website!
Find the two remaining vertices of square ABCD that has A=(-2,1), B=(6,-5) and a vertex in quadrant III.
AB=SQRT((6+2)^2+(5+1)^2)=10
EQN. OF AB IS
(Y-1)=[(1+5)/(-6-2)](X+2)}
4y-4=-3x-6
3X+4Y=-2
ITS DISTANCE FROM ORIGIN IS 2/5
CD IS PARALLEL TO AB AND IS AT 10 DIUSTANCEB FROM AB OR 10+2/5 =52/5 DISTANCE FROM ORIGIN.
HENCE ITS EQN,IS
3X+4Y=-52................................I..OR...3H+4K=-52 AS C H,K LIES ON IT.
SLOPE OF AB =-3/4
SLOPE OF BC =4/3=
LET C BE H,K
SLOPE OF BC = (K+5)/(H-6)=4/3
3K+15=4H-24
4H-3K=39...........................II
SOLVING I AND II
H=0...K=-13.SO C IS (0,-13)
SIMILARLY FOR D WE CAN FIND
SLOPE OF AD =4/3=
LET D BE H,K
SLOPE OF AD = (K-1)/(H+2)=4/3
3K-3=4H+8
4H-3K=-11...........................III
SOLVING I AND III
H=-8 AND K=-7

RELATED QUESTIONS
find the exact value of the expression using the provided information find cos(A+B)... (answered by lwsshak3)

Quadrilateral ABCD has vertices A(-1,0), B(3,3), C(6,-1), and D(2,-4). Prove that... (answered by checkley77,jojo14344)

Suppose that Parallelogram ABCD has vertices A(2, 4), B(8, 4), C(5, -3) and D(-1, -3).... (answered by KMST)

Square ABCD has vertices A(1,—2) and C(4, 5). What is the area of the... (answered by MathLover1,ikleyn)

If given that tan(A) = 5 in Quadrant III and sin(B) = {{{ 2/3 }}} in Quadrant II, what is (answered by Boreal)

If given that tan(A) = 5 in Quadrant III and sin(B) = {{{ 2/3 }}} in Quadrant II, what is (answered by Fombitz)

Find the exact value of cos(a+b) given that cot b = 1/5 and cos a = 12/13 where a is in... (answered by lwsshak3)

Given Tan(A) = 5 in Quadrant III and Sin(B) = 2/3 in Quadrant II, find Sin(A-B),find... (answered by ikleyn)

If A(3,6) and C(-1,2) are two vertices of a rhombus ABCD, then find the equation of... (answered by ikleyn)