SOLUTION: Ok,Im suppose to find the intercepts of a line in an equation. 3x+4y-12=0

Question 349728: Ok,Im suppose to find the intercepts of a line in an equation. 3x+4y-12=0
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
Hi,
*Note: Solving for y puts the equation into the slope-intercept form:
General form is: y = mx + b where m is the slope and b th y-intercept
3x+4y-12=0
.
solving for y
y = (-3/4)*x + 3
.
y- intercept is 3 (0,3) a point on the line with a slope of (-3/4)line slants to the left
x-intercept is 4 (4,0)a point on the line (Note as y decreased by 3, x increased by 4)

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