SOLUTION: equation through (0.-8) and perpindicular to 15x-5y=-8.

Algebra.Com
Question 337698: equation through (0.-8) and perpindicular to 15x-5y=-8.
Answer by Fombitz(32388)   (Show Source): You can put this solution on YOUR website!
Convert the line to slope-intercept form.


Perpendicular lines have slopes that are negative reciprocals,



.
.

The y-intercept (b) is (0,-8).

.
.
.

RELATED QUESTIONS

-8x+5y=3 Find the equation of line through 18,15 parallel to -8x+5y=3 and perpindicular. (answered by dabanfield)
write the equation of the line perpindicular to X+3Y-12=0 and passing through point (-5,... (answered by MathLover1)
Write an equation in slope-intercept form of a line that passes through the points, (2,... (answered by Alwayscheerful)
what is the standard form of the equation of the line passing through the point (-2,-2)... (answered by Maths68)
find an equation of the line through (0,4) and perpindicular to... (answered by checkley71)
Find the equation of the line passing through (-1,2) and perpindicular to... (answered by stanbon)
find the equation of the line parallel to 3x-5y=-7 and goes... (answered by checkley77)
find an equation of the line through (8,-4) and parallel to... (answered by josmiceli)
Find the equation of the straight line through (-1,1) perpendicular to the line 2x - 5y + (answered by lwsshak3)