SOLUTION: Find the distance between the two points: (-3, 22) and (-14, 35) My incorrect answers 5 and sqrt(290). (9, -0) and (-3, -8) My incorrect answers 4 and 5. What is the rad

Algebra ->  Coordinate-system -> SOLUTION: Find the distance between the two points: (-3, 22) and (-14, 35) My incorrect answers 5 and sqrt(290). (9, -0) and (-3, -8) My incorrect answers 4 and 5. What is the rad      Log On


   

Question 329133: Find the distance between the two points:
(-3, 22) and (-14, 35)
My incorrect answers 5 and sqrt(290).
(9, -0) and (-3, -8)
My incorrect answers 4 and 5.
What is the radius of a circle with the given center that passes through the given point?
C (0, 0); Z (-8, 0)
My incorrect answers 4 and 8.
C (-5, 9); Z (6, 0)
My incorrect answers sqrt(173) and sqrt(202).
I would be grateful if someone could explain how they got the answers to these problems. Cheers!
Found 2 solutions by solver91311, Fombitz:
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


Why do you have two answers to a distance question?

Use the distance formula:



where and are the coordinates of the given points.

So for your first problem:



, but is prime.

Hence

is as simple it gets.

The rest of your problems are done exactly the same way, just change the numbers.


John

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Use the distance formula.
The distance between two points only yields 1 number.
D%5E2=%28x1-x2%29%5E2%2B%28y1-y2%29%5E2
D%5E2=%28-3-%28-14%29%29%5E2%2B%2822-35%29%5E2
D%5E2=%28-3%2B14%29%5E2%2B%28-13%29%5E2
D%5E2=%2811%29%5E2%2B%28-13%29%5E2
D%5E2=121%2B169
D%5E2=290
D=sqrt%28290%29
The distance between (-3, 22) and (-14, 35) is sqrt%28290%29.
Follow the same procedure to get the distance for the remaining problems.
.
.
.
The distance from the center of the circle to any point on the circle is equal to the radius of the circle.
Again use the distance formula, but the distance you're calculating now is equal to the radius of the circle.
Again, the radius is only one number.
R%5E2=%28xc-x%29%5E2%2B%28yc-y%29%5E2
where (xc,yc) is the center of the circle and (x,y) is the point on the circle.
R%5E2=%280-%28-8%29%29%5E2%2B%280-0%29%5E2
R%5E2=8%5E2
R=8
The circle centered at (0,0) with point (-8,0) on the circle has a radius of 8.