SOLUTION: Find the center of a circle with the equation:x^2+y^2-6x + 10y +24 = 0

Question 279776: Find the center of a circle with the equation:x^2+y^2-6x + 10y +24 = 0

Found 2 solutions by Fombitz, scott8148:
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
Complete the square in x and y.

The general equation for a circle centered at (h,k) with a radius R is:

This circle is centered at (3,-5).

Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
x^2 + y^2 - 6x + 10y = -24

x^2 - 6x + 9 + y^2 + 10y + 25 = 10

(x - 3)^2 + (y + 5)^2 = 10

center is (3, -5)
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