SOLUTION: using substitution to solve each system of quations for
x=8y-10
x=4y-5
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Question 272576: using substitution to solve each system of quations for
x=8y-10
x=4y-5
Answer by oberobic(2304) (Show Source): You can put this solution on YOUR website!
x=8y-10
x=4y-5
.
x - 8y = -10
x - 4y = -5
subtract
-4y = -5
y = 5/4
.
substituting
x = 8y -10
x = 8(5/4) - 10 = 0
.
Solution: (0, 5/4)
.
Check by inspecting the graphs:
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