SOLUTION: Please help me solves these urgent problems!!! first system 1. x^2+y^2=16 2x+y=4 second system 2. x^2+y^2=4 y=x^2-2

Question 272295: Please help me solves these urgent problems!!!
first system
1. x^2+y^2=16
2x+y=4

second system
2. x^2+y^2=4
y=x^2-2
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
first system
1. x^2+y^2=16
2x+y=4 --> y = -2x+4
Sub for y into the 1st eqn
x^2 + (-2x+4)^2 = 16
x^2 + 4x^2 -16x + 16 = 16
5x^2 - 16x = 0
x = 0
x = 16/5
---------
Solve for y on the line, not the circle, to avoid extraneous roots
x = 0, y = 4 --> (0,4)
x = 16/5, y = -12/5 --> (3.2,-2.4)
-----------------------
second system
2. x^2+y^2=4
y=x^2-2 --> x^2 = y+2
Sub for x^2
(y+2) + y^2 = 4
y^2 + y - 2 = 0
(y+2)*(y-1) = o
y = 1, y = -2
---------------
x^2 = y+2
x^2 = 0 --> (0,-2)
-------------------
x^2 = 3 --> (sqrt(3),1) and (-sqrt(3),1)

RELATED QUESTIONS
Could someone please help me solve the following non-linear system: x^2/4-y^2/16=1 y=x (answered by Alan3354)

URGENT (HELP) HELP ME SOLVE THIS SYSTEM OF EQUATIONS 4X^2-Y^2=4... (answered by solver91311,MathLover1)

Please help me solve the following problems. Solve each system by graphing. 1.... (answered by lyra)

please help me solve each system of equation 1.) y=3x-4 2.) x-2y=-14 3.) x+2y=4 (answered by jeselle)

Can you please help me solve the system ? x\4 - y\3 = -3\4 (answered by ankor@dixie-net.com)

Please help me solve this; solve system by graphing x+y=4 and... (answered by jim_thompson5910)

solve each system..(please) and (thanks:) 1. y=2x+8 y=3x-1 2. 2x-y=2... (answered by stanbon)

Please help me solve this system of equations for all intersections. (4/x^2)+ (6/y^4) (answered by Alan3354)

please help me solve this graphing problem Solve the following system: y = 2x - (answered by jim_thompson5910)