SOLUTION: Solve the following system of equations algebraically:
2y = 8 − x
y − 2x = −1
Algebra.Com
Question 252502: Solve the following system of equations algebraically:
2y = 8 − x
y − 2x = −1
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
put the two equations in the same order
2y=8-x
y=2x-1
y=-1+2x (A)
2y=8-x (B)
multiply (A) by 2
2y=-2+4x (C)
2y=8-x (B)
2y=2+4x (c)
subtract C from B
0=6-3x
subtract 6 from both sides
6=3x
divide both sides by -3
2=x
substitute 2 for x in any equation
2y=8-x
2y=8-(2)
2y=8-2
2y=6
y=3
x=2
check
y=2x-1
3=2(2)-1
3=3
ok
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