SOLUTION: how do i solve 8y-3(4-2y)=6(y+1)?

Question 246956: how do i solve 8y-3(4-2y)=6(y+1)?
Found 2 solutions by checkley77, stanbon:
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
8y-3(4-2y)=6(y+1)
8y-12+6y=6y+6
14y-6y=6+12
8y=18
y=18/8
y=2.25
8*2.25-3(4-2*2.25)=6(2.25+1)
18-3(4-4.5)=6*3.25
18-3*-.5=19.5
18+1.5=19.5
19.5=19.5
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
solve 8y-3(4-2y)=6(y+1)
---
Apply the distributive law to get:
8y-12+6y = 6y+6
---
8y = 18
y = 9/4
===========
Cheers,
Stan H.
RELATED QUESTIONS
How do I solve -3/8y =... (answered by Alan3354)
Help how do I solve... (answered by jim_thompson5910)
I'm stumped. Solve for Y 4(2y-5)=2(4y-10) 8y-20=8y-20 8y-20+20=8y-20+20 8y=8y... (answered by venugopalramana)
How do I solve... (answered by vleith)
Hi how do I solve 2y/3 + 5y/4 = y/6 - 8 Thank... (answered by mananth)
How do you solve: 2y/3-4=y/6-1... (answered by jim_thompson5910)
How would I solve these systems? 1)x+5y=4 3x-7y=-10 2)-5x+3y=6 x-y=4 (answered by elima)
How do I solve for this using substitution. 5x+8y=18... (answered by oberobic,Mathematicians)
How do I solve 12x+8y=4 (answered by richwmiller)