SOLUTION: 32. Write an equation of the line containing the given point and parallel to the given line. Express in form y = mx + b (-5,6); 6x=5y+3

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Question 237338: 32. Write an equation of the line containing the given point and parallel to the given line. Express in form y = mx + b
(-5,6); 6x=5y+3

Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!
Start with the given equation.


Subtract 3 from both sides.


Rearrange the equation.


Divide every term by 5 to isolate 'y'.


Solved by pluggable solver: Finding the Equation of a Line Parallel or Perpendicular to a Given Line


Since any two parallel lines have the same slope we know the slope of the unknown line is (its from the slope of which is also ). Also since the unknown line goes through (-5,6), we can find the equation by plugging in this info into the point-slope formula

Point-Slope Formula:

where m is the slope and (,) is the given point



Plug in , , and



Distribute



Multiply



Add to both sides to isolate y

Make into equivalent fractions with equal denominators



Combine the fractions



Reduce any fractions

So the equation of the line that is parallel to and goes through (,) is


So here are the graphs of the equations and



graph of the given equation (red) and graph of the line (green) that is parallel to the given graph and goes through (,)



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