SOLUTION: How do I find the plotting points and the the y-intercept? y=4/3x+2

Question 227638: How do I find the plotting points and the the y-intercept?
y=4/3x+2
Found 2 solutions by jim_thompson5910, drj:
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!

Looking at we can see that the equation is in slope-intercept form where the slope is and the y-intercept is

Since this tells us that the y-intercept is .Remember the y-intercept is the point where the graph intersects with the y-axis

So we have one point

Now since the slope is comprised of the "rise" over the "run" this means

Also, because the slope is , this means:

which shows us that the rise is 4 and the run is 3. This means that to go from point to point, we can go up 4 and over 3

So starting at , go up 4 units

and to the right 3 units to get to the next point

Now draw a line through these points to graph

So this is the graph of through the points and
Answer by drj(1380) (Show Source): You can put this solution on YOUR website!
How do I find the plotting points and the the y-intercept

Step 1. First to draw this line, we need two points. Here, are Step-By-Step videos on how to plot the lines:

http://www.freedomuniversity.tv/courses/IntroAlgebra/Module3.html

Step 2. This equation is in slope-intercept form given as y=mx+b where m is the slope and b is the y-intercept when x=0 or at point (0,b). So in this example the slope is and the y-intercept is when x=0 or at point (0,2). We have the y-intercept as one point at (0,2).

Step 3. To plot other points choose a value of x and then find y. For example, let x=3, then for the equation then y=4*3/3+2=6. So one point is (3, 6).

Step 4. Now we have two points (0,2) from Step 2 and (3,6) from Step 3 to draw our line. The graph of the line using these points is shown below

.

I hope the above steps were helpful.

For free Step-By-Step Videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra or for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.

And good luck in your studies!

Respectfully,
Dr J

http://www.FreedomUniversity.TV
http://www.Facebook.com/FreedomUniversity.TV
http://www.Twitter.com/FreedomUTV

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