SOLUTION: solve for x: log(x + 2) + log(x-1)=1

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solve for x: log(x + 2) + log(x-1)=1
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log[(x+2)(x-1)] = 1
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(x+2)(x-1) = 10^1
x^2 + x - 2 = 10
x^2 + x -12 = 0
(x+4)(x-3) = 0
x = -4 or x = 3
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Only x=3 is a true solution as log(x+2) and log(x-1) would
be meaningless if x = -4.
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Cheers,
Stan H.