SOLUTION: Suppose f(x) is an odd function whose domain is all real numvers. If the ordered pair(5,-2) is on the graph of y = f(x), then another ordered pair on the graph is (-2,5), (-5,-2)

Question 202697: Suppose f(x) is an odd function whose domain is all real numvers. If the ordered pair(5,-2) is on the graph of y = f(x), then another ordered pair on the graph is (-2,5), (-5,-2), (-5,2), (2,-5)????? thanks for your assistance.
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Recall that if a function f(x) is an odd function, then . Recall that f(x) is another way of saying "y". So when we plug in -x, we get -y. What this means in terms of the point (x,y), the point (-x,-y) is guaranteed to be on the function also. Since (x,y)=(5,-2), this means that (-x,-y)=(-5,2)

So the answer is (-5,2)

If none of the explanation above made any sense, all I did was change the signs of both coordinates.
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