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Question 166772: The center of a circle is on the line x + 2y = 4 The circle passes through points A (6,9) and B (12,-9) Write the equation of the circle.
sq. root ((9-(-x/2+2)^2 + (6-x)^2 ) - sq. root ((-9-(-x/2+2)^2 + (12-x)^2) = 0
x=100, y=-48 But these numbers don't check
Thanks in advance,
Mark
Answer by solver91311(12126)   (Show Source):
You can put this solution on YOUR website! is correct, however express it this way:
Now square both sides:
Collect terms:
Expand the binomials:
The 2nd degree terms fall out:
Collect terms:
 so  , hence center at (6,-1)
Radius squared: 
Equation: 
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