SOLUTION: The center of a circle is on the line x + 2y = 4 The circle passes through points A (6,9) and B (12,-9) Write the equation of the circle. sq. root ((9-(-x/2+2)^2 + (6-x)^2 ) -

Question 166772: The center of a circle is on the line x + 2y = 4 The circle passes through points A (6,9) and B (12,-9) Write the equation of the circle.
sq. root ((9-(-x/2+2)^2 + (6-x)^2 ) - sq. root ((-9-(-x/2+2)^2 + (12-x)^2) = 0
x=100, y=-48 But these numbers don't check
Thanks in advance,
Mark
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
is correct, however express it this way:

Now square both sides:

Collect terms:

Expand the binomials:

The 2nd degree terms fall out:

Collect terms:

so , hence center at (6,-1)

Radius squared:

Equation:
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