# SOLUTION: What is the equation of the perpendicular bisector of the line between the points (2,2) and (6,6)?

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 Click here to see ALL problems on Coordinate-system Question 166434: What is the equation of the perpendicular bisector of the line between the points (2,2) and (6,6)?Answer by nerdybill(6951)   (Show Source): You can put this solution on YOUR website! What is the equation of the perpendicular bisector of the line between the points (2,2) and (6,6)? . ref: http://www.purplemath.com/modules/midpoint.htm . The midpoint between the points using the "mid-point formula" is ((x1+x2)/2, (y1+y2)/2) ((2+6)/2, (2+6)/2) ( 8/2, 8/2) ( 4, 4) (this is the mid-point) . Now, find the slope of the two points: m=(y2-y1)/(x2-x1) m=(6-2)/(6-2) m=4/4 m=1 (this is the slope of the two points) . The perpendicular bisector now has to have a "negative reciprocal" of 1 so our NEW line should have a slope of -1. . So, our new line has: slope = -1 crossing (4,4) . y=mx + b plugging in our info: 4=(-1)4 + b 4= -4 + b 8 = b . Finally, we have: m = -1 b = 8 so, y = -x + 8 (THIS is what they're looking for)