SOLUTION: Using the factoring methd, solve for the roots of each quadraic equation. Place equation in standard form before factoring.
x^2 + 3 - 40=0
x^2 = 10x - 24
p^2 +15p + 25 = 6p + 5
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Question 159991This question is from textbook Beginning Algebra
: Using the factoring methd, solve for the roots of each quadraic equation. Place equation in standard form before factoring.
x^2 + 3 - 40=0
x^2 = 10x - 24
p^2 +15p + 25 = 6p + 5
This question is from textbook Beginning Algebra
Found 2 solutions by Fombitz, checkley77:
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
x=5,-8
.
.
.
x=4,6
.
.
.
p=-4,-5
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
x^2 + 3 - 40=0
(x+8)(x-5)=0
x=-8 answer
x-5=0
x=5 answer.
-------------------------------
x^2 = 10x - 24
x^2-10x+24=0
(x-6)(x-4)=0
x-6=0
x=6 answer.
x-4=0
x=4 answer.
--------------------------------
p^2 +15p + 25 = 6p + 5
p^2+15p-6p+25-5=0
p^2+9p+20=0
(p+4)(p+5)=0
p+4=0
p=-4 answer.
p+5=0
p=-5 answer.
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