SOLUTION: wihtout graphing, decide whether the points would lie on the graph of the equation. 2x+4y=20 a. (6,2) b. (2,4) c. (10,4)

Algebra ->  Algebra  -> Coordinate-system -> SOLUTION: wihtout graphing, decide whether the points would lie on the graph of the equation. 2x+4y=20 a. (6,2) b. (2,4) c. (10,4)      Log On

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 Question 131260: wihtout graphing, decide whether the points would lie on the graph of the equation. 2x+4y=20 a. (6,2) b. (2,4) c. (10,4)Answer by bucky(2189)   (Show Source): You can put this solution on YOUR website!The points you are given are in the form (x, y) ... the first number in the parentheses being the value of x and the number following the comma being the value in y. All you have to do for each of the given points is to substitute the x value for x in the equation and then also substitute the corresponding y value. If the equation still balances, then the point is on the graph. So let's try this process for each of the three points. First point is (6, 2) ... do x is 6 and y is 2. Substitute these two values for x and y in the given equation as follows: . 2x + 4y = 20 . 2(6)+ 4(2) = 20 . do the two multiplications on the left side to get . 12 + 8 = 20 . And since the left side of the equation equals the right side, the point (6, 2) is on the graph. . Now the second point ... (2, 4). Substitute 2 for x and 4 for y: . 2x + 4y = 20 . 2(2)+ 4(4) = 20 . do the two multiplications on the left side to get . 4 + 16 = 20 . The left side of this equation equals the right side so the point (2, 4) is also on the graph. . Finally, the last point ... (10, 4) .... . 2x + 4y = 20 . 2(10)+ 4(4) = 20 . do the two multiplications on the left side to get . 20 + 16 = 20 . This time the left side does not equal the right side. Because of this you can say that the point (10, 4) is NOT on the graph. . Hope this helps you to understand the problem and how to answer it. . .