SOLUTION: PLEASE HELP ME ANSWER THIS PROBLEM: -2[(-K-3)(-2)-3]=(-3-3K)(-2)TO THE POWER OF 3 THEN MINUS 3 TO THE POWER OF 2 THANK YOU SO MUCH!

Algebra ->  Algebra  -> Coordinate-system -> SOLUTION: PLEASE HELP ME ANSWER THIS PROBLEM: -2[(-K-3)(-2)-3]=(-3-3K)(-2)TO THE POWER OF 3 THEN MINUS 3 TO THE POWER OF 2 THANK YOU SO MUCH!      Log On

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Question 120260This question is from textbook
: PLEASE HELP ME ANSWER THIS PROBLEM:

-2[(-K-3)(-2)-3]=(-3-3K)(-2)TO THE POWER OF 3 THEN MINUS 3 TO THE POWER OF 2
THANK YOU SO MUCH!This question is from textbook

Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
-2[(-k-3)(-2)-3]=(-3-3k)(-2)^3-3^2
-2[(2k+6)-3]=(-3-3k)(-8)+9
-2[2k+6-3]=24+24k+9
-2[2k+3]=33+24k
-4k-6=33+24k
-4k-24k=33+6
-28k=43
k=43/-28
k=-43/28 answer.