Do it in three steps.


(1)  Find y-intercept.  

     For it, substitute x= 0 into the equation and get y= 6/(-2) = -3.
     Thus y-intercept is the point (0,-3).
     Draw this point and call it A.


(2)  Then use the slope. From the given equation, the slope is -1/2.

     From the y-intercept point (0,-3), go 2 units horizontally to the right parallel to x-axis
                                       and 1 unit  vertically down parallel to y-axis.
     You will arrive to the point (2,-4).
     Draw this point and call it B.


(3)  Using a straightedge and a pencil, connect two points A and B by the pencil.
     It will give you the desired line.

First get the equation in slope-intercept form, y = mx + b, by
solving for y

Give x the coefficient 1


Divide through by -2





Comparing that to y = mx + b we see that the slope m is ,
and the y-intercept b is -3.

We plot the y-intercept at -3 on the y-axis:



Begin by looking at the numerator and sign of the slope.  The slope is . 
Its numerator is 1, and its sign is -

Since the sign of the slope is NEGATIVE, we draw a line DOWNWARD from the 
y-intercept. It's the vertical blue line below.

[If the sign of the slope had been POSITIVE we would have drawn a line UPWARD].  



Next, we look at the denominator of the slope.  The slope is . Its
denominator is 2.  We always go to the RIGHT with the denominator.  So from
the bottom of the blue line we draw a horizontal line to the right 2 units:



Now we take a straight edge and draw a line through the point where we started,
at the y-intercept, and through the point where we ended up.


Edwin