.
Since the projected/requested line is parallel to the given line, its equation has the same co-named coefficients at x and y.
Hence, the projected/requested line has an equation of the form 2x - 3y = c with unknown coefficient "c".
To find "c", simply substitute the coordinates of the given point p and q as x and y respectively into this equation 2x - 3y = c.
You will get
2*3 - 3*(-10) = c,
which implies c = 6 + 30 = 36.
Thus your final equation of the projected/requested line in standard form is
2x - 3y = 36. ANSWER
What you really need to know to solve such problems is THIS:
1. Two parallel lines have the same slope. It helps you when you are dealing with the slope-intersept form of equations.
Therefore, the equations of parallel lines are identical in their "x-y" parts. The difference is only in their constant terms.
2. Two parallel lines have the same co-named coefficients in their standard form.
Therefore, the equations of parallel lines are identical in their "x-y" parts. The difference is only in their constant terms.
3. To find the unknown constant term in the equation for the projected/requested parallel line, simply substitute the coordinates of the
given point into this equation.
See the lesson
- Equation for a straight line parallel to a given line and passing through a given point
in this site.