So the equation is now in slope-intercept form () where (the slope) and (the y-intercept)
So to graph this equation lets plug in some points
Plug in x=-2
So here's one point (-2,9)
Now lets find another point
Plug in x=-1
So here's another point (-1,6). Add this to our graph
Now draw a line through these points
So this is the graph of through the points (-2,9) and (-1,6)
So from the graph we can see that the slope is (which tells us that in order to go from point to point we have to start at one point and go down -3 units and to the right 1 units to get to the next point), the y-intercept is (0,)and the x-intercept is (,0) . So all of this information verifies our graph.
We could graph this equation another way. Since this tells us that the y-intercept (the point where the graph intersects with the y-axis) is (0,).
So we have one point (0,)
Now since the slope is , this means that in order to go from point to point we can use the slope to do so. So starting at (0,), we can go down 3 units
and to the right 1 units to get to our next point
Now draw a line through those points to graph
So this is the graph of through the points (0,3) and (1,0)