SOLUTION: f={(1,2),(2,3),(3,3)},g={(1,0)(2,3),(3,2),(4,8)} Find the range of f+g=

Algebra.Com
Question 1128255: f={(1,2),(2,3),(3,3)},g={(1,0)(2,3),(3,2),(4,8)}
Find the range of f+g=

Answer by greenestamps(13334)   (Show Source): You can put this solution on YOUR website!


f+g is only defined for values of x in the domains of both f and g: {1,2,3}. f+g is not defined for x=4, because 4 is in the domain of only g, not f.

We aren't going to run into any problems with function values being undefined for the function f+g, so there will be three values in the range of f+g.

(f+g)(1) = 2+0 = 2
(f+g)(2) = 3+3 = 6
(f+g)(3) = 3+2 = 5

ANSWER: The range of f+g is {2,5,6}

RELATED QUESTIONS

Use the functions f(x) = 2x +7, g(x) = x squared + 3x, and h(x) = 1/x-7 to find each of... (answered by funmath)
if f=3/g, where g is not equal to 0 and f is not equal to 1, which of the following is... (answered by math_tutor2020,greenestamps,josgarithmetic)
Given f(x)=x/(x-1) , g(x)=(2x-4)/x find the following a) (f•g)(0) b) (g•f)(-2)... (answered by stanbon)
f={(1,2),(2,3),(3,3),(4,5)},g={(1,1)(2,3),(3,2),(4,8)} Find... (answered by CubeyThePenguin)
f={(1,2),(2,3),(3,3),(4,5)},g={(1,1)(2,3),(3,2),(4,8)} Find... (answered by CubeyThePenguin)
given f(x)=√2x-1 and g(x)= x^2+1,x grater then or equal to 0 1.without finding (answered by MathLover1)
f={(1,2),(2,3),(3,3),(4,5)},g={(1,1)(2,3),(3,2),(4,8)} ① Find (f*g)(2)= ②... (answered by CubeyThePenguin)
suppose f(x)=3x-4 and g(x)=x+3.. find each value.. 6. f(2) 7.f(1/3)+g(-2)... (answered by Mathtut)
x | 0 | 1 | 2 | 3 | 4 f(x) | 3 | 4 | 0 | 2 | 1 g(x) | 2 | 1 | 3 | 4 | 0 Find... (answered by only4christ2)
Find (g ° f)(4) for the functions below: F(x)=x+3, g(x) = 1/x^2 (g ° f)(4) = (answered by Alan3354)