SOLUTION: Find an equation of the circle whose center is at the point (-3 , 6) and is tangent to the y axis. I figure the answer would be (x+3)^2+(y-6)^2=9 but however at this moment the

Question 1088136: Find an equation of the circle whose center is at the point (-3 , 6) and is tangent to the y axis.
I figure the answer would be (x+3)^2+(y-6)^2=9 but however at this moment there isn't anyway to prove the answer to whether to be correct or wrong. Thank you very much!
Found 2 solutions by ikleyn, Fombitz:
Answer by ikleyn(52946) (Show Source): You can put this solution on YOUR website!
.
= ,

or

= 9.

Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
Use the general equation of a circle of radius R centered at (h,k),

Since it's tangent to the y-axis, (0,6) is also on the circle,

So,

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.
.
.

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