SOLUTION: How would I write the equation of a line that has slope -3 and contain the point(4,2).express final equation in standard form. Showing me how to solve this would be of great assis

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Question 107078: How would I write the equation of a line that has slope -3 and contain the point(4,2).express final equation in standard form. Showing me how to solve this would be of great assistance.
Thank you,
Brina

Found 2 solutions by Annabelle1, MathLover1:
Answer by Annabelle1(69)   (Show Source): You can put this solution on YOUR website!
you use your point-gradient formula again
y-y1=m(x-x1)
where m=-3 and x1,y1 is your point (4,2)
(x1=4,y1=2)
subbing into the equation
y-2=-3(x-4)
expand
y-2=-3x+12
y+3x-2-12=0
y+3x-14=0

Answer by MathLover1(20850)   (Show Source): You can put this solution on YOUR website!

here is solution:

Solved by pluggable solver: FIND a line by slope and one point

What we know about the line whose equation we are trying to find out:

  • it goes through point (4, 2)

  • it has a slope of -3



First, let's draw a diagram of the coordinate system with point (4, 2) plotted with a little blue dot:



Write this down: the formula for the equation, given point and intercept a, is

(see a paragraph below explaining why this formula is correct)

Given that a=-3, and , we have the equation of the line:



Explanation: Why did we use formula ? Explanation goes here. We are trying to find equation y=ax+b. The value of slope (a) is already given to us. We need to find b. If a point (, ) lies on the line, it means that it satisfies the equation of the line. So, our equation holds for (, ): Here, we know a, , and , and do not know b. It is easy to find out: . So, then, the equation of the line is: .

Here's the graph:




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