SOLUTION: PARABOLA: what's the vertex, focus, directrix, latus rectum and graph of the y^2+16x=0
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Question 1039252: PARABOLA: what's the vertex, focus, directrix, latus rectum and graph of the y^2+16x=0
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Put the equation into vertex form. Since the 
variable is squared, this is a parabola with a horizontal axis of symmetry and a vertical directrix. Vertex form for such a parabola is the equation solved for 
in terms of everything else.
Rewrite so that the elements of the vertex form are evident:
^2\ +\ 0)
The general form of a parabola with a horizontal axis is:
^2\ +\ h)
Which is a parabola with a horizontal axis,
vertex at )
,
parameter 
,
directrix equation: 
,
focus at )
,
and latus rectum endpoints at )
.
I'll help you find the parameter 
:
The rest is just plugging in numbers.
John
My calculator said it, I believe it, that settles it
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