SOLUTION: Directions: Find the equation of a circle satisfying the conditions given, then sketch its graph:
Problem: Center at (-8,3), graph contains the point (-3,15)
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Question 1026004: Directions: Find the equation of a circle satisfying the conditions given, then sketch its graph:
Problem: Center at (-8,3), graph contains the point (-3,15)
Answer by richard1234(7193) (Show Source): You can put this solution on YOUR website!
Equation is of the form ^2 + (y-3)^2 = r^2)
where r is the radius of the circle.
We know that (-8,3) -- (-3,15) is a radius, so to find r (or r^2), we use the distance formula:
)^2 + (3 - 15)^2 = (-5)^2 + (-12)^2 = 13^2 = 169)
So the equation of the circle is ^2 + (y-3)^2 = 169)
.
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