Questions on Algebra: Coordinate systems, graph plotting, etc answered by real tutors!

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Tutors Answer Your Questions about Coordinate-system (FREE)


Question 739009: graph the following system of equations using slope and y intercept determine the number of solutions for the system, 2x+3y=6 and 4x+6y=24
Answer by tommyt3rd(440) About Me  (Show Source):
You can put this solution on YOUR website!
graph%28+300%2C+200%2C+-10%2C+10%2C+-10%2C+10%2C+-.67%2Ax%2B2%2C+-.67%2Ax%2B6+%29
these two lines clearly have the same slope yet they have different y-intercepts, so they must be parallel. Therefore the number of solutions is 0



Question 739295: Find the slope of a line perpendicular to each given line. y=-5/3x+3
Answer by tommyt3rd(440) About Me  (Show Source):
You can put this solution on YOUR website!
the perpendicular slope is the negative reciprocal of the original so it is 3/5

:)


Question 728156: Write the equation in standard form of the circle with the given properties.
Center at the origin; r = square root of 7

Answer by tommyt3rd(440) About Me  (Show Source):
You can put this solution on YOUR website!
origin => C(0,0) with r=sqrt%287%29
so

%0D%0A%28x-h%29%5E2%2B%28y-k%29%5E2=r%5E2%0D%0A

becomes

%0D%0Ax%5E2%2By%5E2=7%0D%0A

:)


Question 748429: What linear equation represents a line containing the point (1,3)?
Answer by MathLover1(6618) About Me  (Show Source):
You can put this solution on YOUR website!
y=mx..........linear equation
if a line containing the point (1,3)
3=m
so, linear equation represents a line containing the point (1,3) is
y=3x



Question 748408: What is the slope of the line that passes through the points (3,5) and (-2,2)?
Answer by rfer(12646) About Me  (Show Source):
You can put this solution on YOUR website!
m=(2-5)/(-2-3)
m=-3/-5
m=3/5


Question 748386: A computer-aided design (CAD) operator has located three corners of a rectangle. The corners are at (8, 12), (-5, 12), and (-5, 6). Plot these points and find the location of the fourth corner.
I need help with this please

Answer by josgarithmetic(1476) About Me  (Show Source):
You can put this solution on YOUR website!
Obviously the y coordinate of the unknown corner is 6. One of the sides is 13 units horizontally. From (-5,6) to (x, 6) to be 13 units, you must have x=8.


Question 748072: The distance between the two points A(a,1,2) and B(5,a,3) is 3. Find the value of .
Answer by tommyt3rd(440) About Me  (Show Source):
You can put this solution on YOUR website!
If you mean find the value of a, then here we go:

It's convenient to use distance squared in this case (why?)

%0D%0A3%5E2=%285-a%29%5E2%2B%28a-1%29%5E2%2B%283-2%29%5E2%0D%0A


%0D%0A9=%2825-10a%2Ba%5E2%29%2B%28a%5E2-2a%2B1%29%2B%0D%0A1


and after some simplifying and rearranging
%0D%0A2a%5E2-12a-18=0%0D%0A
then
%0D%0Aa%5E2-6a-9=0%0D%0A

which is a perfect square and tells us a=3



Question 747424: Factor x3+1000:
Answer by lenny460(755) About Me  (Show Source):
You can put this solution on YOUR website!
Factor: x^3 + 1000

We can solve the above using the sum of cubes formula:

Answer:
(x + 10)(x^2 - 10x + 100)





Lennox Obuong
Algebra Tutor
Nairobi, Kenya
Email: obuong3@aol.com


Question 746036: i have tried but cant seem to figure it out !!p is the midpoint of line AB. what are the coordinates of point p? A(120) B(120)
Answer by Alan3354(30968) About Me  (Show Source):
You can put this solution on YOUR website!
i have tried but cant seem to figure it out !!p is the midpoint of line AB. what are the coordinates of point p? A(120) B(120)
-----------------
A and B don't have (x,y) coordinates.
What does the (120) mean?


Question 745468: The ordinate of a point which is √29 units from (5,1) is twice its abscissa. Find the point.
Answer by sachi(392) About Me  (Show Source):
You can put this solution on YOUR website!
as per question the point is (x,2x)
so the distance from (5,1)
is √[(x-5)^2+(2x-1)^2]=√29
or (x-5)^2+(2x-1)^=29
or x^2-10x+25+4x^2-4x+1=29
or 5x^2-15x-3=0
or 5x^2-15x-x-3=0
or (x-3)(5x+1)=0
or x=3 or -1/5
so y=6 or -2/5
so the points are (3,6) or (-1/5,-2/5)


Question 745466: Express by an algebraic equation the statement that the point (x,y) is at a distance 3 from (-7,-3)
Answer by stanbon(57224) About Me  (Show Source):
You can put this solution on YOUR website!
Express by an algebraic equation the statement that the point (x,y) is at a distance 3 from (-7,-3)
-----
sqrt[(x+7)^2+(y+3)^2] = 3
==============================
Cheers,
Stan H.


Question 744087: I am using substitution to find coordinates for x and y. Problem reads: 2x+3y=25 , where y=3x+1.
I understood that to be 2x+3*(3x+1)=25,
Using distributive property, now I have 2x+9x+1=25.
Simplified that to 11x=24, or x=24/11
My textbook shows the correct final answer for coordinates is x=2, y=7, so I am way off. Can you tell where I went wrong?

Answer by stanbon(57224) About Me  (Show Source):
You can put this solution on YOUR website!
I am using substitution to find coordinates for x and y.
Problem reads:
2x+3y=25
y = 3x+1
----------------------
I understood that to be 2x+3*(3x+1)=25,
Using distributive property, now I have 2x+9x+3 = 25.
Simplified that to 11x=22, or x = 2
Solve for "y":
y = 3x+1
y = 3*2+1 = 7
========================
My textbook shows the correct final answer for coordinates is x=2, y=7
========================
Cheers,
Stan H.


Question 742906: Plot the number 3/2 on a number line
Answer by rfer(12646) About Me  (Show Source):

Question 742659: where would you plot y=x on a graph?
Answer by stanbon(57224) About Me  (Show Source):
You can put this solution on YOUR website!
where would you plot y=x on a graph?
-----
Plot 2 points:
Let x = 1, then y = 1 giving you point (1,1)
-----
Let x = 3, then y = 3 giving you point (3,3)
=============
Cheers,
Stan H.
=============


Question 742331: .)Given the equation of a basic graph and describe a sequence of transformation that can be used to find the graph of y=-|2x-3| DONOT GRAPH .
Basic graph equation:__________
Transformations:

10.)Calculate an equation for the circle for which the segment represent PQ is a diameter
P=(-3,1) , Q=(5,6)

Answer by stanbon(57224) About Me  (Show Source):
You can put this solution on YOUR website!
Given the equation of a basic graph and describe a sequence of transformation that can be used to find the graph of y=-|2x-3| DONOT GRAPH .
Basic graph equation: y = |x|
Transformations:
1st: horizontal stretch by factor of 2
2nd: shift 3 units to the right
3rd: reflect in the x-axis
=====================================
10.)Calculate an equation for the circle for which the segment represent PQ is a diameter
P=(-3,1) , Q=(5,6)
-----
Find Center (x,y)
x = (-3+5)/2 = 1
y = (6+1)/2 = 3.5
---------------------
Find the Radius:
r = sqrt[(-3-1)^2 + (1-3.5)^2] = sqrt[16+6.25] = sqrt(22.25)
------
Equation:
(x+3)^2 + (Y-1)^2 = 22.25
=============================
Cheers,
Stan H.


Question 742329: Help!
6.)find the function that is finally graphed after the following transformations in indicated order are applies to the graph of y=|x|
1.) Right shift by 4 units
2.) Reflection with respect to the x-axis
3.) Horizontal stretch by a factor of 2
4.) Shift downwards by 2 units

Answer by stanbon(57224) About Me  (Show Source):
You can put this solution on YOUR website!
6.)find the function that is finally graphed after the following transformations in indicated order are applies to the graph of
y=|x|
1.) Right shift by 4 units
y = |x-4|
----------
2.) Reflection with respect to the x-axis
y = -|x-4|
---------------
3.) Horizontal stretch by a factor of 2
y = -2|x-4|
-----------------------
4.) Shift downwards by 2 units
y = -2|x-4|-2
=================
Cheers,
Stan H.
=================


Question 742325: Can someone assist me??please.
i)state the transformations applied to the graph of f(x)=|x| to obtain the graph of g(x)=-2|x-3|+1
ii)Sketch the graph.Show and label at least 3 points of transformations used to draw your graph.

Answer by stanbon(57224) About Me  (Show Source):
You can put this solution on YOUR website!
Can someone assist me??please.
i)state the transformations applied to the graph of f(x)=|x| to obtain the graph of g(x)=-2|x-3|+1
-----
1st: shift 3 to the right
2nd: reflect in the x-axis
3rd: stretch by a factor of 2
4th: vertical transformation of +1
-----------------------------------------------
ii)Sketch the graph.Show and label at least 3 points of transformations used to draw your graph.
graph%28400%2C400%2C-10%2C10%2C-10%2C10%2C-2%2Aabs%28x-3%29%2B1%29
--------------------------------------------------
Cheers,
Stan H.


Question 740984: PLEASE HELP ME SOLVE THIS!!!
Point "A" (-4,1) is in the standard (x,y) coordinate plane. What must be the coordinates of point "B" so that the line x = 2 is the perpendicular bisector of "AB", with a line drawn above "AB"?

Answer by ankor@dixie-net.com(15628) About Me  (Show Source):
You can put this solution on YOUR website!
Point "A" (-4,1) is in the standard (x,y) coordinate plane.
What must be the coordinates of point "B" so that the line x = 2 is the perpendicular bisector of "AB", with a line drawn above "AB"?
;
Since the bisector is a vertical line, line AB is a horizontal line.
:
The best way to understand this is use graph paper. Draw the x/y, point -4,1;
the line for x=2 is a vertical line going thru x=2, will cross Line AB at x/y point 2,1
As you can see, Line AB will between points -4,1 and 8,1


Question 740020: Find the circumference of each circle. Use 3.14 for Pie. Round to the nearest tenth
10 in.

Answer by Alan3354(30968) About Me  (Show Source):
You can put this solution on YOUR website!
Find the circumference of each circle. Use 3.14 for Pie. Round to the nearest tenth
10 in.
------------
You didn't say what the 10 inches is.
If it's radius,
C = 2*pi*r
--------------
PS It's the Greek letter pi, not the dessert pie.


Question 739893: find the slope of the line passing through the given points (-1/3, 1/5) and (3/2, 1/4)
Answer by Alan3354(30968) About Me  (Show Source):
You can put this solution on YOUR website!
find the slope of the line passing through the given points
(-1/3, 1/5) and (3/2, 1/4)
------------
m = diffy/diffx = (1/20)/(11/6)
m = 3/110


Question 25265: USE THE GRAPHING METHOD TO TELL HOW MANY SOLUTIONS THE SYSTEM HAS:
x+y=8
x+y=-1

Answer by jam123(17) About Me  (Show Source):
You can put this solution on YOUR website!
x+y = 8, so
y = 8-x
x+y=-1 so
y=-1-x
+graph%28+700%2C+700%2C+-5%2C+5%2C+-5%2C+5%2C+8-x%2C+-1-x%29+
The lines are parallel so there are no solutions.


Question 739518: HOW DO YOU FIND ORDERED PAIRS IF YOU DO NOW KNOW THE EQUATION

Answer by AnlytcPhil(1276) About Me  (Show Source):
You can put this solution on YOUR website!
If you will, in the thank-you note space, state the 
problem and instructions exactly word-for-word as it 
is stated in your book, I will answer it.

Phil


Question 739298: Find the slope of a line perpendicular to each given line. y=2/3x+4
Answer by Alan3354(30968) About Me  (Show Source):
You can put this solution on YOUR website!
Find the slope of a line perpendicular to each given line. y=2/3x+4
==========================
Slope of the given line is 2/3
Slope of lines perpendicular is the negative inverse of 2/3.


Question 739059: find the value of the missing coordinate in (x,5)that makes the orderd pair a solution to the equation 2x+y=-1
Answer by opie95(4) About Me  (Show Source):
You can put this solution on YOUR website!

put your y coordinate in and solve the equation
2x+5=-1
2x=-6
x=-3
subtract 5 from both sides which gives you -6
divide both sides by 2
x=-3


Question 739025: find the slope of a line parallel to each given line. y=2
Answer by reviewermath(500) About Me  (Show Source):
You can put this solution on YOUR website!
y = 2 is a horizontal line, therefore the slope of any line
parallel to it is highlight%280%29 (zero).


Question 739021: Can you please help me. I need to find the slope of a line parallel to each given line. y=3/4x
Answer by rfer(12646) About Me  (Show Source):
You can put this solution on YOUR website!
parallel slope is still 3/4


Question 738551: Can you please help me find the slope of a line perpendicular to each given line. y=-5/3x+3
Answer by MathLover1(6618) About Me  (Show Source):
You can put this solution on YOUR website!
given line: y=-%285%2F3%29x%2B3...compared to slope-intercept form y=mx%2Bb, you see that slope m=-%285%2F3%29
the slope of a line perpendicular to given line will have a slope m%5Bp%5D=-1%2Fm
so, a slope is m%5Bp%5D=%28%28-1%29%2F%28-5%2F3%29%29 => m%5Bp%5D=%28-1%2A3%29%2F-5 => m%5Bp%5D=3%2F5


Question 738549: please help me find the slope of a line parallel to each given line. y=-2x+1
Found 2 solutions by MathLover1, jim_thompson5910:
Answer by MathLover1(6618) About Me  (Show Source):
You can put this solution on YOUR website!

you are given a line +y=-2x%2B1, and it is already in slope-intercept form y=mx%2Bb where m=slope and b=y-intercept
so, the slope of given line +y=-2x%2B1 is m=-2
by definition, a line parallel to given line has same slope; so, m%5Bp%5D=-2

Answer by jim_thompson5910(28476) About Me  (Show Source):
You can put this solution on YOUR website!
The slope of this line is -2

The slope of ANY line parallel to this one will also be -2 since all parallel lines have the same slope

So the answer is -2


Question 738547: Can you please help me find the slope of a line perpendicular to each given line. y=1/2x-5
Answer by jim_thompson5910(28476) About Me  (Show Source):
You can put this solution on YOUR website!
The slope of this given line is 1/2

Flip the fraction to get 2/1 = 2

Flip the sign to get -2, this is the perpendicular slope. A good way to remember finding it is: Start with the given slope, turn it into a fraction (if necessary), then flip the fraction and flip the sign to get the perpendicular slope.

So the answer is -2


Question 738360: Can you please help me find the slope of the line parallel to each given line.
y=-x-1

Answer by jim_thompson5910(28476) About Me  (Show Source):
You can put this solution on YOUR website!
y = -x-1 is the same as y = -1x-1 which is in the form y = mx+b

So the slope is m = -1

All lines parallel to this one will also have a slope of -1 since parallel lines have equal slopes

So the final answer is -1


Question 738359: Can you please help me find the slope of the line parallel to each given line.
y=x-1

Answer by jim_thompson5910(28476) About Me  (Show Source):
You can put this solution on YOUR website!
y = x - 1 has a slope of 1 since it's in the form y = mx+b where m = 1

ANY line parallel to this one will also have a slope of 1 because any two parallel lines have the same slope.

So the answer is 1


Question 738262: Can you please help me find the slope of the line through each pair of points.
(-6,2),(7,2)

Answer by richwmiller(9135) About Me  (Show Source):
You can put this solution on YOUR website!
y=2 is the line
since y doesn't change the slope is zero


Question 738201: What are the coordinates of the point 3 units from the y-axis at a distance √5 from (5,3)?
Answer by josgarithmetic(1476) About Me  (Show Source):
You can put this solution on YOUR website!
This would be difficult to use the system to show a drawing and graph, but I am handling it like:

The line x=3, y=infinity,
A segment with endpoint at (5,3) and perpendicular to the line x=3, will be seen to intersect the line x=3 AT the point (3, 3).
EITHER of two points are also on the line x=3, and each of these is sqrt%285%29 from the point (5, 3), but we do not yet know the y coordinate for this point.
... BUT we DO have a triangle, actually a RIGHT triangle and we can find the length up or down from point (3, 3) using pythagorean theorem.

From (3, 3) to (5, 3) is 2 units.
From (5, 3) to (3, u) is sqrt%285%29 units.
From (3, u) to (3, 3) is h
Let's find h using pythagorean theorem.
h%5E2%2B2%5E2=%28sqrt%285%29%29%5E2
highlight%28h=1%29
Therefore, u=3-1, u=2.
ANSWER: The coordinate pair for the specified point is then either (3, 2) or (3, 4).


Question 738113: can you please help me find the slope of the line (7,14),(16,-8). I came up with -9/22
Answer by DrBeeee(376) About Me  (Show Source):
You can put this solution on YOUR website!
Your answer is upside down. The slope is
(1) m = (y1-y2)/(x1-x2) or
(2) m = (14-(-8))/(7-16) or
(3) m = 22/(-9) or
(4) m = -22/9


Question 738040: I need help finding the slope of the line through each pair of points.
(19,11),(20,13).. I came up with 1/2


Answer by rfer(12646) About Me  (Show Source):
You can put this solution on YOUR website!
m=(13-11)/(20-19)
m=2/1
m=2


Question 737672: I need to find the slope. (19,-6),(-15,9). Thank you!
Answer by reviewermath(500) About Me  (Show Source):
You can put this solution on YOUR website!
The slope is equal to %289-%28-6%29%29%2F%28-15-19%29+=+highlight%28-15%2F34%29


Question 736662: I am confused on this problem.
Find the equation for the circle with a diameter whose endpoints are (-3,-5)(-5,4).

Answer by lynnlo(4155) About Me  (Show Source):
You can put this solution on YOUR website!
(x+4)^2+(y+1/2)^2


Question 736571: i need help with graphing -2x-y=-2

Answer by stanbon(57224) About Me  (Show Source):
You can put this solution on YOUR website!
i need help with graphing -2x-y=-2
---------
Solve for "y":
y = -2x+2
-----
Plot 2 points:
(0,2) and (1,0)
-------
Draw a line thru those two points:
graph%28400%2C400%2C-10%2C10%2C-10%2C10%2C-2x%2B2%29
------------
Cheers,
Stan H.
==========


Question 736459: I am so lost can you please help? I need to solve and graph y=-x
Found 2 solutions by josmiceli, Alan3354:
Answer by josmiceli(9654) About Me  (Show Source):
You can put this solution on YOUR website!
Make a chart that has columns labeled +x+ and +y+
Under the +x+ column, you will pick values that are
pretty close to +0+, like:
-10, -9, -8, -7, -6, -5, -4, -3, -2, -1, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10
( remember: write these vertically )
Now alongside each of these values for +x+, you will fill in a
value for +y+
+y+=+-x+
+y+=+-%28-10%29+
+y+=+10+
-------------
+y+=+-x+
+y+=+-%28-9%29+
+y+=+9+
-----------
etc.
When you get to +x+=+0+,
+y+=+-x+
+y+=+-0+
+y+=+0+
-----------
+y+=+-x+
+y+=+-1+
----------
+y+=+-2+
----------
etc.
After you have filled the chart, each pair of ( x,y )
entries is a point that you will plot, so you
have the points:
( -10, 10 )
( -9, 9 ),
( -8, 8 ),
etc.
For plotting, the origin is (0,0) and positive x is to the right,
negative x is to the left, positive y is up, and
negative y is down.
You will end up with the following plot:
+graph%28+500%2C+500%2C+-12%2C+12%2C+-12%2C+12%2C+-x+%29+
You can plot any equation with this method


Answer by Alan3354(30968) About Me  (Show Source):
You can put this solution on YOUR website!
Same as this one:
------------
solve and graph y=x-2
================
It is solved for y.
You can solve for x: x = y+2
--------------
It's 1 equation in 2 variables, --> an infinite # of solutions.
y = x-2
You can pick any number for x and find y.
----
To graph it, you need 2 points.
Pick 2 values for x and find y.
x = 0, y = -2 --> point (0,-2)
x = 2, y = 0 --> point (2,0)
x = 100, y = 98 --> (100,98)
------
Plot at least 2 points, draw a line thru them.
Every point on the line is a "solution."


Question 736458: Can you please help me solve and graph y=x-2? It has been a very long time since I have done this and I am lost.
Answer by Alan3354(30968) About Me  (Show Source):
You can put this solution on YOUR website!
solve and graph y=x-2
================
It is solved for y.
You can solve for x: x = y+2
--------------
It's 1 equation in 2 variables, --> an infinite # of solutions.
y = x-2
You can pick any number for x and find y.
----
To graph it, you need 2 points.
Pick 2 values for x and find y.
x = 0, y = -2 --> point (0,-2)
x = 2, y = 0 --> point (2,0)
x = 100, y = 98 --> (100,98)
------
Plot at least 2 points, draw a line thru them.
Every point on the line is a "solution."


Question 736303: what is or how do you simplify this expression -7(2v+6)-2
Answer by lynnlo(4155) About Me  (Show Source):
You can put this solution on YOUR website!
PROBLEM:
-7(2V+6)-2
EXPAND "-7"BY USING ASSOCIATIVE PROPERTY ON(2V+6)
-7(2V-7)6-2
MULTIPLY INTEGERS
-14V-7(6-2)
MULTIPLY INTEGERS
-14V-42-2
ADD INTEGERS TOGETHER
-14V+-44
REMOVE (+)IN FRONT OF "-44"
ANSWER======-14V-44


Question 734960: Write an equation of the line that passes through the given point and is perpendicular to the graph of the given equation. (-8,3) y+4=-(2/3)(x-2)
Answer by josgarithmetic(1476) About Me  (Show Source):
You can put this solution on YOUR website!
Interesting that you showed your given line in almost correctly point-slope form as plain text. Your post is now edited for this correction to eliminate possible confusion, ------

The slope that you will want is the negative reciprocal of %28-%282%2F3%29%29, which will be 3%2F2. You now expect an equation for your desired line to be y-v=%283%2F2%29%2A%28x-u%29, where the point (u, v) is any point which you want your line to contain. The given point for (u, v) is (-8, 3), so just substitute those values:
y-%283%29=%283%2F2%29%2A%28x-%28-8%29%29
and the rest to be done is a couple steps of arithmetic.


Question 734984: Two lines in a coordinate plane have no points of intersection. Which of these could be the equations of the lines?
A. 4x+2y=6 C.4x+=6
10x+5y=7 5x-10y=6
B. 4x+2y=6 D. 5x+10y=6
10x+5y=15 5x-10y=6

Answer by lynnlo(4155) About Me  (Show Source):

Older solutions: 1..45, 46..90, 91..135, 136..180, 181..225, 226..270, 271..315, 316..360, 361..405, 406..450, 451..495, 496..540, 541..585, 586..630, 631..675, 676..720, 721..765, 766..810, 811..855, 856..900, 901..945, 946..990, 991..1035, 1036..1080, 1081..1125, 1126..1170, 1171..1215, 1216..1260, 1261..1305, 1306..1350, 1351..1395, 1396..1440, 1441..1485, 1486..1530, 1531..1575, 1576..1620, 1621..1665, 1666..1710, 1711..1755, 1756..1800, 1801..1845, 1846..1890, 1891..1935, 1936..1980, 1981..2025, 2026..2070, 2071..2115, 2116..2160, 2161..2205, 2206..2250, 2251..2295, 2296..2340, 2341..2385, 2386..2430, 2431..2475, 2476..2520, 2521..2565, 2566..2610, 2611..2655, 2656..2700, 2701..2745, 2746..2790, 2791..2835, 2836..2880, 2881..2925