SOLUTION: Construct a truth table for the statement, (p <--->q) --->p
Any help would be greatly appreciated. Or an example of a very similar problem with the exact same punctuations etc. Pl
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Question 729129: Construct a truth table for the statement, (p <--->q) --->p
Any help would be greatly appreciated. Or an example of a very similar problem with the exact same punctuations etc. Please help!!! Thank you
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Here's what the completed table looks like
Keep in mind that p <--> q is only true if BOTH p AND q have the same truth value (ie both are true or false together)
Also, p --> q is only false when p is true and q is false. Otherwise it's true.
| p |
q |
p <--> q |
(p <--> q) --> p |
| T |
T |
T |
T |
| T |
F |
F |
T |
| F |
T |
F |
T |
| F |
F |
T |
F |
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