SOLUTION: construct a truth table for the following:
1. ~p-> q
2. ~(p->q)
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Question 588459: construct a truth table for the following:
1. ~p-> q
2. ~(p->q)
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
# 1
| p |
q |
~p |
~p -> q |
| T |
T |
F |
T |
| T |
F |
F |
T |
| F |
T |
T |
T |
| F |
F |
T |
F |
========================================================================
# 2
| p |
q |
p -> q |
~(p -> q) |
| T |
T |
T |
F |
| T |
F |
F |
T |
| F |
T |
T |
F |
| F |
F |
T |
F |
Notes:
1) ~p is the opposite of p. So if p is true, then ~p is false. If p is false, then ~p is true.
2) p -> q is only false when both p is true and q is false. Otherwise, p -> q is true.
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